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Jquery, reading JSON variables received from PHP

开发者 https://www.devze.com 2023-01-11 15:18 出处:网络
Sorry if this is basic, but I have been dealing with figuring this out all day and have gotten to where I can do everything I need with Jquery and cakephp (not sure if cakephp matters in this or if it

Sorry if this is basic, but I have been dealing with figuring this out all day and have gotten to where I can do everything I need with Jquery and cakephp (not sure if cakephp matters in this or if its same as any PHP), I want to return a variable from a cakephp function to jquery, I had read about how to do it, like here:

the cakephp:

$test[ 'mytest'] = $test;
 echo json_encode($test);

and the jquery:

$.ajax({
  type: 'POST',
  url: 'http://localhost/site1/utilities/ajax_component_call_handler',
  data: {
        co开发者_如何学JAVAmponent_function: component_function,
        param_array: param_array
        },
        dataType: "json",
  success: function(data) {
   // how do i get back the JSON variables? 
  }
});

I just can't figure out how to get one or more variables back into usable form within jquery, I just want the variable so I can do whatever else with it, I've been looking at what I can find through searching but its not making it fully clear to me.. thanks for any advice.


The JSON variables are in the data variable. In your case, it'll look like this:

var data = {
    myTest: "Whatever you wrote here"
};

... so you can read it from data.myTest.

(Not sure whether it's relevant but you can remove the http://localhost/ part from the URL; AJAX does not allow cross-domain requests anyway.)


Your variables are in data.

$.ajax({
  type: 'POST',
  url: 'http://localhost/site1/utilities/ajax_component_call_handler',
  data: {
        component_function: component_function,
        param_array: param_array
        },
        dataType: "json",
  success: function(data) {
   // how do i get back the JSON variables? 
      var values = eval( data ); //if you 100 % trust to your sources.
  }
});


Basically data variable contain the json string. To parse it and convert it again to JSON, you have to do following:

$.ajax({
  type: 'POST',
  url: 'http://localhost/site1/utilities/ajax_component_call_handler',
  data: {
        component_function: component_function,
        param_array: param_array
        },
        dataType: "json",
  success: function(data) {
   json = $.parseJSON(data);
   alert(json.mytest);
  }

I haven't test it but it should work this way.


Note that when you specify dataType "json" or use $.getJSON (instead of $.ajax) jQuery will apply $.parseJSON automatically.

So in the "success" callback you do not need to parse the response using parseJSON again:

success: function(data) {
 alert(data.mytest);
}


In case of returning a JSON variable back to view files you can use javascript helper:

in your utilities controller:

function ajax_component_call_handler() {
  $this->layout = 'ajax';
  if( $this->RequestHandler->isAjax()) {
       $foobar = array('Foo' => array('Bar'));
       $this->set('data', $foobar);
  } 
}

and in your view/utilities/ajax_component_call_handler.ctp you can use:

if( isset($data) ) {
   $javascript->object($data); //converts PHP var to JSON
}

So, when you reach the stage in your function:

 success: function(data) {
   console.log(data); //it will be a JSON object.    
 }

In this case you will variable type handling separated from controllers and view logic (what if you'll need something else then JSON)...

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