How to get the HTML output of a drupal node having php code?

I have a node with the following content (inp开发者_JS百科ut mode: php code):

this is a <?php echo "test" ?>

If I output node->body, the output is

this is a <?php echo "test" ?>

What I want is:

this is a test

What is the easiest way to do this?

(I don't want all the default divs and other structural stuff coming with it when I call node_view)

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You should enable (shipped with core) "php.module", which comes with an input-formatter, PHP-filter. That filter allows you to insert php as you mention in nodes. And will eval() that for you on output.

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It sounds like you don't use the php filter that's needed to do something like this. The result is your code is escaped.

On a random drupal install I just tested:

This is a <?php echo 'test'; ?>

Outputs

This is a test

When I view the node.

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In Drupal, to display html output of a node which have 'PHP Filter' you can do this

echo php_eval(node->body);

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You could output

eval($node->body); // be sure what you are evaling