I think this is a question that has been asked many times but I cannot find the right way to do it.
I have the following structure:
project/
project/Makefile
project/code
project/code/*.cc
project/code/Makefile
开发者_StackOverflow社区
When I am in the directory 'project/code' and call "make project_code" my code is compiling correctly.
I would like to do that when I am in 'project/', just calling "make project_code" as if I was in 'project/code'.
The makefile 'project/Makefile' will contain other rules (such as 'install') and some rules to compile as if I was in 'project/code'. And for that, I am requesting your help... Thanks.
The simplest way is to do:
CODE_DIR = code
.PHONY: project_code
project_code:
$(MAKE) -C $(CODE_DIR)
The .PHONY rule means that project_code is not a file that needs to be built, and the -C flag indicates a change in directory (equivalent to running cd code before calling make). You can use the same approach for calling other targets in the code Makefile.
For example:
clean:
$(MAKE) -C $(CODE_DIR) clean
Try putting this rule in project/Makefile something like this (for GNU make):
.PHONY: project_code
project_code:
cd code && make
加载中,请稍侯......
精彩评论