I'm going through my code to replace any instances I'm using the ereg() function - which I was using for matching regex inside a string.
I could use a little direction, if someone has a better method than what I'm using.
Here's my old "currency validation开发者_C百科" script:
function valid_currency($number){
if(ereg('^[0-9]+\.[0-9]{2}$', $number))
return true;
else
return false;
}
if(valid_currency(25.30)){
echo "valid currency";
}else{
echo "invalid currency string";
}
I replaced the ereg() with preg_match().
I'm getting this error now:
Warning: preg_match() [function.preg-match]: No ending delimiter '^'
I'm guessing the regular expression syntax isn't being recognized. From here I'm a little stuck.
preg requires delimiters around your regex. It can be almost anything though traditionally it's /. This should work:
preg_match('/^[0-9]+\.[0-9]{2}$/', $number)
You need the bounds for the regex statement, IE it's thinking you're starting the statement with ^ and saying there's no ending ^ indicating the end of the statement. Use /^[0-9]+\.[0-9]{2}$/
instead
in preg_match() or preg_match_all() uses "delimiters".examples:
/regEx/ or #regEx# or |regEx| or @regEx@.
I use: /regEx/
function valid_currency($n) {
return preg_match("/^\d+\.\d{2}$/", $n);
}
returns bool: 1(true) 0(false)
exmaple of use:
echo valid_currency("25.30") ? 'valid currency' : 'invalid currency string';
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