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What is the simplest way to get a ratio in PHP of multiple numbers?

开发者 https://www.devze.com 2023-01-11 10:34 出处:网络
I\'ve adapted this from an example that I found on the \'net... function ratio($a, $b) { $_a = $a; $_b = $b;

I've adapted this from an example that I found on the 'net...

function ratio($a, $b) {
    $_a = $a;
    $_b = $b;

    while ($_b != 0) {

        $remainder = $_a % $_b;
        $_a = $_b;
        $_b = $remainder;   
    }

    $gcd = abs($_a);

    return ($a / $gcd)  . ':' . ($b / $gcd);

}

echo ratio(9, 3); // 3:1

Now I want it to use func_get_args() an开发者_高级运维d return the ratios for multiple numbers. It looks like a recursive problem, and recursion freaks me out (especially when my solutions infinitely loop)!

How would I modify this to take as many parameters as I wanted?

Thanks


1st, try this gcd function http://php.net/manual/en/function.gmp-gcd.php Or else you must define a gcd function like

    function gcd($a, $b) {
        $_a = abs($a);
        $_b = abs($b);

        while ($_b != 0) {

            $remainder = $_a % $_b;
            $_a = $_b;
            $_b = $remainder;   
        }
        return $a;
    }

Then modify the ratio function

    function ratio()
    {
        $inputs = func_get_args();
        $c = func_num_args();
        if($c < 1)
            return ''; //empty input
        if($c == 1)
            return $inputs[0]; //only 1 input
        $gcd = gcd($input[0], $input[1]); //find gcd of inputs
        for($i = 2; $i < $c; $i++) 
            $gcd = gcd($gcd, $input[$i]);
        $var = $input[0] / $gcd; //init output
        for($i = 1; $i < $c; $i++)
            $var .= ':' . ($input[$i] / $gcd); //calc ratio
        return $var; 
    }
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