Could you please tell me what the equivalent BASH code for the fol开发者_开发百科lowing C++ snippet would be:
std::cout << std::setfill('x') << std::setw(7) << 250;
The output is:
xxxx250
Thanks for the help!
If you're on Linux, it has a printf
program for just this purpose. Other UNIX variants may also have it.
Padding a numeric with x
is not really on of its use cases but you could get the same result with:
pax> printf "%7d\n" 250 | tr ' ' 'x'
xxxx250
That outputs the 250 with space padding, then uses the tr
translate utility to turn those spaces into x
characters.
If you're looking for a bash
-only solution, you can start with:
pax> n=250 ; echo ${n}
250
pax> n=xxxxxxx${n} ; echo ${n}
xxxxxxx250
pax> n=${n: -7} ; echo ${n}
xxxx250
If you want a generalised solution, you can use this function fmt
, unit test code is included:
#!/bin/bash
#
# fmt <string> <direction> <fillchar> <size>
# Formats a string by padding it to a specific size.
# <string> is the string you want formatted.
# <direction> is where you want the padding (l/L is left,
# r/R and everything else is right).
# <fillchar> is the character or string to fill with.
# <size> is the desired size.
#
fmt()
{
string="$1"
direction=$2
fillchar="$3"
size=$4
if [[ "${direction}" == "l" || "${direction}" == "L" ]] ; then
while [[ ${#string} -lt ${size} ]] ; do
string="${fillchar}${string}"
done
string="${string: -${size}}"
else
while [[ ${#string} -lt ${size} ]] ; do
string="${string}${fillchar}"
done
string="${string:0:${size}}"
fi
echo "${string}"
}
# Unit test code.
echo "[$(fmt 'Hello there' r ' ' 20)]"
echo "[$(fmt 'Hello there' r ' ' 5)]"
echo "[$(fmt 'Hello there' l ' ' 20)]"
echo "[$(fmt 'Hello there' l ' ' 5)]"
echo "[$(fmt 'Hello there' r '_' 20)]"
echo "[$(fmt 'Hello there' r ' .' 20)]"
echo "[$(fmt 250 l 'x' 7)]"
This outputs:
[Hello there ]
[Hello]
[ Hello there]
[there]
[Hello there_________]
[Hello there . . . . ]
[xxxx250]
and you're not limited to just printing them, you can also save the variables for later with a line such as:
formattedString="$(fmt 'Hello there' r ' ' 20)"
You can print padding like this:
printf "x%.0s" {1..4}; printf "%d\n" 250
If you want to generalize that, unfortunately you'll have to use eval
:
value=250
padchar="x"
padcount=$((7 - ${#value}))
pad=$(eval echo {1..$padcount})
printf "$padchar%.0s" $pad; printf "%d\n" $value
You can use variables directly in brace sequence expressions in ksh, but not Bash.
s=$(for i in 1 2 3 4; do printf "x"; done;printf "250")
echo $s
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