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call another applet in an applet

开发者 https://www.devze.com 2022-12-09 11:54 出处:网络
I want to call (just display another applet)one applet from another applet . I just placed a button on my first applet and on its actionperformed method

I want to call (just display another applet)one applet from another applet . I just placed a button on my first applet and on its actionperformed method used the getcontextapplet() method. But second applet was not displayed.

How can I display a second applet on any reaction of first...

The code:

import java.io.*;
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.sql.*;
import javax.swing.*;
public class home extends Applet implements ActionListener
{
    Container c1;
    Label l1,l2,l3,l4;
    TextField t1;
    Button b1,b2;
    ImageIcon icon;
    Panel p1;
    URL order;

    public void init()
    {
        // Tell the applet not to use a layout manager. 
        setLayout(null); 



        l1=new Label("MINDSOFT CONSULTANTS");
        Font fg=new Font("Times new roman",Font.BOLD,50);
        add(l1);
        l1.setFont(fg);
        l1.setBounds(20,20,800,70);

        l2=new Label("Strength of 5000 employees");
        fg=new Font("Times new roman",Font.BOLD,25);
        l2.setFont(fg);
        l2.setBounds(180,120,500,30);
        add(l2);

        l3=new Label("Specialised in IT and computing services");
        l3.setFont(fg);
        l3.setBounds(90,180,500,30);
        add(l3);

        l4=new Label("A total of 10 different departments");
        l4.setFont(fg);
        l4.setBounds(140,240,500,30);
        add(l4);

        b1=new Button("VIEW DETAIL");
        b1.setBounds(150,320,150,40);
        add(b1);
        b1.addActionListener(this);

        b2=new Button("ADD DETAIL");
        b2.setBounds(450,320,150,40);
        add(b2);

        try
   开发者_开发技巧     {
        order =new URL("C:\Documents and Settings\Administrator\Desktop\try\add.html");   
        }
        catch(MalformedURLException e){
        System.out.println("HH");
        }


    }

    public void actionPerformed(ActionEvent e)
    {

        if(e.getSource()==b1)
        {
        getAppletContext().showDocument(order);
        System.out.println("HI");
        }

    }
}   


If you're still seeing an "Illegal Escape Character" error on line 57, it's down to the string literal you're passing when instantiating order:

order =new URL("C:\Documents and Settings\Administrator\Desktop\try\add.html");   

The Java Escape Character is the backslash (\). Therefore, every time you use a back slash, the compiler thinks you're trying to escape the character that follows it. For example, in the string

C:\Documents

...the compiler is treating \D as a single escaped character rather than as two characters. The compiler error you're seeing is telling you that it doesn't recognise some of the escaped characters (\D, \A, \t) in that string.

The solution is to escape the escape character, e.g. prefix each backslash with a blackslash:

order =new URL("C:\\Documents and Settings\\Administrator\Desktop\\try\\add.html"); 

This tells the compiler to treat the backslashes as backslashes, rather than as escape characters.


Try http://www.wutka.com/hackingjava/ch10.htm or simply Google for inter applet communication

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