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RabbitMQ Message Consumption ID based (c# API)

开发者 https://www.devze.com 2023-01-11 00:37 出处:网络
i would like to publish/produce a message with some message id, like each message has a particular id..

i would like to publish/produce a message with some message id, like each message has a particular id..

And at the consumer end i would like to retrieve the messages by prividing the ID. suppose we have multiple consumers than each one should get only those messages which they requested t开发者_如何学JAVAhrough the message ids. (i hope i am clear enough).


Although its not by design and its better to use a database for that there is a way to do this using rabbitmq:

Publish a message with id:

var message = "some message";
var messageId = Guid.NewGuid().ToString();
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    IBasicProperties props = channel.CreateBasicProperties();
    props.MessageId = messageId;

    byte[] messageBodyBytes = Encoding.UTF8.GetBytes(message);

    channel.BasicPublish("", "queueName", true, props, messageBodyBytes);
}

Get a message by id:

var messageId = "id";
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = _factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    var queueDeclareResponse = channel.QueueDeclare("queueName", true, true, false, null);

    for (int i = 0; i < queueDeclareResponse.MessageCount; i++)
    {
        var result = channel.BasicGet("queueName", false);
        var id = result.BasicProperties.MessageId;

        if (id == messageId)
        {
            var body = result.Body;
            var message = Encoding.UTF8.GetString(body);

            //Do something with the message

            channel.BasicAck(result.DeliveryTag, false);
            break;
        }
    }
}

After channel is disposed all messages that was not acked will requeue.


You might be better off using a database for this.

alexis (rabbitmq)

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