The title of this question might be a bit off but its the cl开发者_JAVA技巧osest I could get to what I am trying to do.
I have a Products model which has_many Comments. I am looking to come up with a way to grab the top 10 Products with the most comments. Is this possible?
At the moment I have:
Product.find(:all, :limit => 10)
This gets me my 10 products, but it obviously does not consider how many comments each product has.
Cheers
Eef
If you have a counter cache column on Product for Comment then you can do this with a simple :order_by
on that column.
Edit: Taking animal's comment into account:
class Product < ActiveRecord::Base
has_many :comments,
:counter_cache => true
end
You will need a column on products
called comments_count
:
add_column :products, :comments_count, :integer, :null => false, :default => 0
Alternatively if you don't want to alter your model you can use find_by_sql to specify a subselect which will tell you how many comments each product has and order by that. E.g.
Post.find_by_sql("SELECT products.*
FROM products, (SELECT COUNT(*)
FROM comments WHERE comments.product_id = products.id) AS product_comment_count
ORDER BY product_comment_count DESC
LIMIT 10")
You might need to adjust the syntax to be specific to whichever RDBMS you are using.
Try this:
Product.all(:select=> "products.*, COUNT(products.id) AS comments_count",
:joins => :comments,
:group => "products.id",
:order => "comments_count",
:limit => 10)
Result is sorted by the comment count and you can access the comments_count
as follows:
@products.each do |product|
p product.comments_count
end
Make sure you have indexed the product_id
column in the comments
table.
Note:
I would use the counter_cache
feature for this requirement(as suggested by @tadman
).
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