What is the syntax for zindex?
I tried like this
document.getElementById('iframe_div1').style.zIndex =2000;
document.getElementById('iframe_div1').style.z-index =2000;
It is not working, it doesn't even show an error.
This is my snippet. It is working fine in HTML, but I want to set this CSS property in jQuery or JavaScript. The top/position attributes are not working...
z-index:1200px; top:450px; position:absolute; right:300px;
document.getElementById('iframe_div1').style.display='block';
$("#iframe_div1").css("z-index", "500");
$("#iframe_div1").css("right", "300");
$("#iframe_div1").css("top", "450");
document.getElementById('iframe_div1').style.position = "absolute";
This snippet is not as perfect as I expect. I want to move my div center of the page, but it just moving my div to the bottom of the page.
document.getElementById('iframe_div1').style.zIndex = "2000";
is fine. Just make sure it's position
is absolute
or relative
. like this,
document.getElementById('iframe_div1').style.position = "relative"; // could also be absolute
The former should work all right. Use a DOM inspector like Firebug's "inspect element" to find out whether maybe the value gets assigned, but doesn't have the desired effect.
In jQuery, it would be
$("#iframe_div1").css("z-index", "2000");
As this link mentions, zIndex
only works if the element was positioned, so are you using something like position: absolute;
?
http://www.w3schools.com/jsref/prop_style_zindex.asp
...but it just moving my div bottom of the page...
becouse:
document.getElementById('iframe_div1').style.display='block';
Must be:
document.getElementById('iframe_div1').style.display='relation';
//or
document.getElementById('iframe_div1').style.display='absolute';
$('#iframe_div1').css({
right : '300px',
top : '450px',
border : '1px solid red',
color : '#f00'
});
Thanks Problem fixed
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