Replace double quotes to single quotes with awk

BEGIN {
    q = "\""
    FS = OFS = q ", " q
}
{ 
    split($1, arr, ": " q)
    for(i in arr ) {
        if(arr[i] == "name") {
            gsub(q, "'", arr[i+1])
            # print arr[1] ": " q arr[2], $2, $3  
        }
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}

I have a json file, some data like this:

{"last_modified": {"type": "/type/datetime", "value": "2008-04-01T03:28:50.625462"}, "type": {"key": "/type/author"}, "name": "National Research Council. Committee on the Scientific and Technologic Base of Puerto Rico"s Economy.", "key": "/authors/OL2108538A", "revision": 1}

The name's value have a double quote, I only want to replace the double quote to single quote , not the all double quote, please tell me how to fix it?

---

awk '{for(i=1;i<=NF;i++) if($i~/name/){ gsub("\042","\047",$(i+1)) }}1' file