I want to delete a record in jqgrid
.
For this I have the image and when the user clicks on this the record is getting deleted.
But I want to show the confirm
box and when true then only the record should get deleted.
So any one can tell how to call javascript in jqgrid
.
My jqgrid is
jQuery(document).ready(function() {
jQuery("#list47").jqGrid({
url: 'AddFilterGrid.aspx?Show=ViewFilter',
datatype: "json",
id: "F开发者_Python百科ilterName",
colNames: ["SubCategory", "Filter", 'Delete', 'Edit'],
colModel: [{
name: 'CategoryName',
index: 'CategoryName',
width: 150,
align: 'left',
sortable: true,
sorttype: 'text'
}, {
name: 'FilterName',
index: 'FilterName',
width: 150,
align: 'left',
sortable: true,
sorttype: 'text'
}, {
name: 'f',
index: 'f',
width: 100,
align: "center",
formatter: 'showlink',
formatter: formateadorLinkDelete
}, {
name: 'FilterId',
index: 'FilterId',
width: 100,
align: "center",
formatter: 'showlink',
formatter: formateadorLinkEdit
},
],
height: 280,
width: 650,
//autowidth: true,
mtype: "GET",
pager: '#plist47',
rowNum: 10,
rowList: [10, 20, 30, 40],
repeatitems: false,
viewrecords: true,
sortname: 'FilterName',
viewrecords: true,
sortorder: "desc",
gridview: true,
imgpath: '/Scripts/themes/redmond/images'
});
});
Make a column with a delete button, give your button an attribute with the id, so you can post that id to delete it.
do a post to your delete controller
$.post('url/delete/$(this).val("deletid")', function(data) {
$('.result').html(data);
});
@ edit: create a delete link in one of your colums, with class="delete" and deleteid="the id" you can create a confirm popup box:
$(function(){
$(.delete).foreach(function(){
$('#dialog').dialog({
autoOpen: false,
width: 400,
modal: true,
resizable: false,
buttons: {
"Submit": function(){
$.post('url/delete/$(this).val("deletid")', function(data) {
//find your tr and hide it
$(this).parent().parent.... .hide();
});
};
},
"Cancel": function() {
$(this).dialog("close");
}
}
});
});
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