I'm going crazy trying to echo an <img>
tag.
I want to add this simple string "/uploads/"
before $photo->name
.
Here is my echo: echo '<img src="'.$photo->开发者_开发技巧name.'"/>';
Thanks for any help.
Not sure if I completely understand, but try this:
echo '<img src="/uploads/'.$photo->name.'"/>';
Here you go:
echo '<img src="/uploads/'.$photo->name.'"/>';
Or:
echo '<img src="' . '/uploads/' . $photo->name.'"/>';
Or:
echo '<img src="' . "/uploads/" . $photo->name.'"/>';
echo '<img src="/uploads/'.$photo->name.'"/>';
How about
echo '<img src="/uploads/'.$photo->name.'"/>';
... unless I'm missing something?
two ways to use echo tag
1st : one is double quotes which use for out put of strings
echo "your name is".$name //here name is variable
2nd : one is single quotes in which you can use all html tags here is the example
<?php
$name="Adil";
echo $name;
for($i=0;$i<44;$i++)
{
echo($i.'<br>') ;
if($i==10)
{
echo ' <table border=3> <tr><td><h1>its image </h1><img src="examp.png" alt="loading" /><td><td>hello</td><tr></table>';
}
}
?>
here i am using multiple tags in echo using
single quotes
if put double quotes then you will see following error Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\Untitled2d.php on line 21
here is the output
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