Giving this kind of XML file :
<data>
<row val="3"/>
<row val="7"/>
<row val="2"/>
<row val="4"/>
<row val="3"/>
</data>
I need to retrieve the string '3;7;2;4;3' using XPath 1.0 so that I can create dynamic links 开发者_开发百科for the Google Chart service in my XForms application.
How can I do that ? Is it possible ?
XPath 2.0 solution:
string-join(/data/row/@val,';')
XSLT 1.0 solution:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="row">
<xsl:value-of select="concat(substring(';',1,position()-1),@val)"/>
</xsl:template>
</xsl:stylesheet>
EDIT: Short XSLT 1.0 solution.
Not possible in XPath (at least, not in XPath 1.0, which I suppose is the version you have).
Using XSLT, this would be easy:
<xsl:template match="/data">
<!-- select all rows for processing -->
<xsl:apply-templates select="row" />
</xsl:template>
<!-- rows are turned into CSV of their @val attributes -->
<xsl:template match="row">
<xsl:value-of select="@val" />
<xsl:if test="position() < last()">
<xsl:text>;</xsl:text>
</xsl:if>
</xsl:template>
XPath is a selection language, not a processing language. You can process the nodes in any other programming language that provides XML and XPath support - XSLT is only one of the options.
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