I have a function that has a return type of Maybe ([(Int,Int)],(Int,Int))
I would like to call this from another function and perform an operation on the data.
However, the return value is contained within Just
. The second method takes ([(Int,Int)],(Int,Int))
and therefore will not accept Just ([(Int,Int)],(Int,Int))
.
Is there a way I can trim the Just
before applying the开发者_JAVA技巧 second method?
I don't fully understand the use of Just
within Maybe
- however, I have been told that the return type for the first Method must be Maybe
.
There are several solutions to your problem, all based around pattern matching. I'm assuming you have two algorithms (since you didn't name them, I will):
algorithm1 :: a -> Maybe b
algorithm2 :: b -> c
input :: a
1) Pattern matching is typically done from either a case statement (below) or a function.
let val = algorithm1 input
in case val of
Nothing -> defaultValue
Just x -> algorithm2 x
All other presented solutions use pattern matching, I'm just presenting standard functions that perform the pattern matching for you.
2) The prelude (and Data.Maybe) have some built-in functions to deal with Maybe
s. The maybe function is a great one, I suggest you use it. It's defined in standard libraries as:
maybe :: c -> (b -> c) -> Maybe b -> c
maybe n _ Nothing = n
maybe _ f (Just x) = f x
Your code would look like:
maybe defaultValue algorithm2 (algorithm1 input)
3) Since Maybe is a functor you could use fmap. This makes more sense if you don't have a default value. The definition:
instance Functor Maybe where
fmap _ Nothing = Nothing
fmap f (Just a) = Just (f a)
So your code would look like:
fmap algorithm2 (algorithm1 input)
This output will be a Maybe
value (Nothing
if the result of algorithm1 is Nothing
).
4) Finally, and strongly discouraged, is fromJust
. Only use it if you are positive the first algorithm will return Just x
(and not Nothing
). Be careful! If you call fromJust val
when val = Nothing
then you get an exception, which is not appreciated in Haskell. Its definition:
fromJust :: Maybe b -> b
fromJust Nothing = error "Maybe.fromJust: Nothing" -- yuck
fromJust (Just x) = x
Leaving your code to look like:
algorithm2 (fromJust (algorithm1 input))
You're looking for fromJust
. But only if you're certain your Maybe
function is not going to return a Nothing
!
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