script as module and executable

• I have a script in python that can be invoked from the command-line and uses optparse.

  script -i arg1 -j arg2
  

  In this case I use (options, args) = parser.parse_args() to create options then use options.arg1 to get arguments.

• But I also want it to be importable as a module.

  from script import *
  function(arg1=a开发者_JS百科rg1, arg2=arg2)
  

  I've managed to do this using a really lame solution: by providing a dummy object.

  def main():
      class Options:
          ''' dummy object '''
          def __init__(self):
              pass
      options = Options
      for k in kwargs:
          setattr(options, k, kwargs[k])
  

The rest of the script doesn't know the difference but I think this solution is fugly.

Is there a better solution to this?

---

Separate the CLI from the workhorse class:

class Main(object):
    def __init__(self,arg1,arg2):
        ...
    def run(self):
        pass

if __name__=='__main__':
    import optparse
    class CLI(object):
        def parse_options(self):
            usage = 'usage: %prog [options]'+__usage__
            parser = optparse.OptionParser(usage=usage)
            parser.add_option('-i', dest='arg1')
            parser.add_option('-j', dest='arg2') 
            (self.opt, self.args) = parser.parse_args()
        def run(self):
            self.parse_options()        
            Main(self.opt.arg1,self.opt.arg2).run()
    CLI().run()

---

What you usually do is:

def foo():
    print 'This is available when imported as a module.'

if __name__ == '__main__':
    print 'This is executed when run as script, but not when imported.'