How to remove numbers from a string with RegEx

I have a string like this:

" 2开发者_开发知识库3 PM"

I would like to remove 23 so I'm left with PM or (with space truncated) just PM.

Any suggestions?

Needs to be in PHP

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echo trim(str_replace(range(0,9),'',' 23 PM'));

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Can do with ltrim

ltrim(' 23 PM', ' 0123456789');

This would remove any number and spaces from the left side of the string. If you need it for both sides, you can use trim. If you need it for just the right side, you can use rtrim.

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preg_replace("/[0-9]/", "", $string);

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Can also use str_replace, which is often the faster alternative to RegEx.

str_replace(array(1,2,3,4,5,6,7,8,9,0,' '),'', ' 23 PM');
// or
str_replace(str_split(' 0123456789'), '', ' 23 PM');

which would replace any number 0-9 and the space from the string, regardless of position.

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If you just want the last two characters of the string, use substr with a negative start:

$pm = substr("  23 PM", -2); // -> "PM"

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$str = preg_replace("/^[0-9 ]+/", "", $str);

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Regex

preg_replace('#[0-9 ]*#', '', $string);

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You can also use the following:

preg_replace('/\d/', '',' 23 PM' );

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trim() will allow a range of characters in the "character mask" parameter by using dot syntax.

Code: (Demo)

//              v--------literal spaces
trim(" 23 PM", ' 0..9')
//               ^^^^----all digits
// output: PM