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How to bind data in heredoc of scala?

开发者 https://www.devze.com 2023-01-09 11:23 出处:网络
val name = \"mike\" val str = \"\"\"Hi, {name}!\"\"\" println(str) I want it outpu开发者_开发问答t the str as Hi, mike!, but failed. How to do this?Scala does not support string interpolation. There
val name = "mike"
val str = """Hi, {name}!"""
println(str)

I want it outpu开发者_开发问答t the str as Hi, mike!, but failed. How to do this?


Scala does not support string interpolation. There is a compiler plugin that implements it at http://github.com/jrudolph/scala-enhanced-strings.

Without the plugin you can use concatenation or format strings:

val str = name formatted "Hi, %s!"

or of course

val str = "Hi, %s!".format(name)


A total hackish solution would be to use Scala's XML interpolation:

val name = "Mike"
val str = <a>Hi, {name}!</a> text

The text method returns string contents of an XML construct, so our tags are stripped.


As of scala >= 2.10 string interpolations are supported:

val str = "Foo Bar"
str: String = Foo Bar

scala> s"Interpolating: $str"
res0: String = Interpolating: Foo Bar
0

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