开发者

Why does calling this function with more than 2 parameters in Actionscript 3 cause stack overflow?

开发者 https://www.devze.com 2023-01-09 08:30 出处:网络
functi开发者_JAVA百科on testFunc(val1:int, val2:int, val3:int):int { var returnVal:int = 0; return returnVal;
functi开发者_JAVA百科on testFunc(val1:int, val2:int, val3:int):int {
    var returnVal:int = 0;
    return returnVal;
}

var val:int = testFunc(1, 2, 3);

causes

locals: Main int int int * 
4:dup VerifyError: Error #1023: Stack overflow occurred.


This page discusses a similar stack overflow issue. It seems adding a trace somewhere in the function will fix it.

It's a known bug


Thank you for pointing this fact out. Anyways here is what I realize.

A function in AS3 is defined as

function apply(thisArg:*, argArray:*):*

i.e any user function will be mapped into adobe defined Function.apply as above. I guess this is something similar to the environment variables in c. The first argument can be used to send the length of the Array of arguments followed by the Array itself.

So this basically means, if you wish to use the above function call you can define your function as

function testFunc(...args):int {

val1:int = args[0];
val2:int = args[1];
val3:int = args[2];

var returnVal:int = 0;
return returnVal;

}

var val:int = testFunc(1, 2, 3);

I did not really find anything around Google though. Which lead me to go to aobe's page itself. Anyways glad that I learned something new.

Edit: Please do look over the function definition here : http://www.adobe.com/livedocs/flash/9.0/ActionScriptLangRefV3/Function.html


Yes it's a bug player, another workaround will be to cast your result to int, so the instruction generated by the compiler will not be the same:

in the first case:

function testFunc(val1:int, val2:int, val3:int):int {
    var returnVal:int = 0;
    return returnVal;
}

the compiler generate something like that: Note that there is nothing wrong with the code generated

getlocal 0
pushscope 
pushbyte 0      // stack = 0
dup             // stack = 0 0
setlocal 4      // set returnVal with value on stack, stack = 0
returnvalue     // return the value left on the stack i.e. 0, stack=empty

and for the workaround:

function testFunc(val1:int, val2:int, val3:int):int {
    var returnVal:int = 0;
    return int(returnVal);
}

the code generated is

getlocal 0
pushscope 
pushbyte 0           // stack = 0
setlocal 4           // set returnValue with the value on the stack, stack=empty
findpropstrict int   // push on stack the object holding the int property, stack=object
getlocal 4           // push on stack returnVal, stack=object 0
callproperty int(param count:1) // call the int property , stack=0
returnvalue          // return the value left on stack i.e 0, stack=empty
0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号