I'm working on this program to get all the files in the directory. For some reason I am getting a NullPointerException on Line 16. I don't know why though since this is a template that seemed to work in class with our teacher. Thanks.
import java.util.*;
import java.io.*;
public class FindDirectories {
public static void main(String[] args) {
if (args.length == 0) {
args = new String[] { ".." };
}
List<String> nextDir = new ArrayList<String>();
nextDir.add(args[0]); // either the one file, or the directory
try 开发者_JAVA技巧{
while(nextDir.size() > 0) { // size() is num of elements in List
File pathName = new File(nextDir.get(0)); // gets the element at the index of the List
String[] fileNames = pathName.list(); // lists all files in the directory
for(int i = 0; i < fileNames.length; i++) {
File f = new File(pathName.getPath(), fileNames[i]); // getPath converts abstract path to path in String,
// constructor creates new File object with fileName name
if (f.isDirectory()) {
System.out.println(f.getCanonicalPath());
nextDir.add(f.getPath());
}
else {
System.out.println(f);
}
}
nextDir.remove(0);
}
}
catch(IOException e) {
e.printStackTrace();
}
}
}
Check out the Javadoc for File.list()
. Specifically:
Returns null if this abstract pathname does not denote a directory, or if an I/O error occurs.
In your code pathName.list();
must be returning null so pathName
does not represent a valid directory, or an IO error occurred trying to get a list of files from that directory.
Use bellow snippet to get all the files from all the sub directories:
import java.io.File;
/**
*
* @author santoshk
*/
public class ListFiles {
File mainFolder = new File("F:\\personal");
public static void main(String[] args)
{
ListFiles lf = new ListFiles();
lf.getFiles(lf.mainFolder);
}
public void getFiles(File f){
File files[];
if(f.isFile())
System.out.println(f.getAbsolutePath());
else{
files = f.listFiles();
for (int i = 0; i < files.length; i++) {
getFiles(files[i]);
}
}
}
}
If you're getting a NullPointerException on line 16, it must mean that fileNames
is null, so fileNames.length
is invalid. Take a look at the javadoc for File.list and you'll see that pathName.list()
can be null if pathName
is not a directory, or if an exception occurs. So you'll just need to check whether fileNames
is null before trying to use it.
import java.io.File;
import java.util.ArrayList;
import java.util.LinkedList;
public class FileEnumerator {
/**
* @param args
* @throws IOException
*/
public static void main(String[] args) throws IOException {
// Prepare the List of files
String path = "C:/";
ArrayList<String> Files = new ArrayList<String>();
LinkedList<String> Dir = new LinkedList<String>();
File f = new File(path);
Dir.add(f.getAbsolutePath());
while(!Dir.isEmpty())
{
f = new File(Dir.pop());
if(f.isFile())
{
Files.add(f.getAbsolutePath());
}
else
{
String arr[] = f.list();
try
{
for(int i = 0;i<arr.length;i++)
{
Dir.add(f.getAbsolutePath()+"/"+arr[i]);
}
}
catch(NullPointerException exp)
{
Dir.remove(f.getAbsoluteFile());
}
}
}
//Print the files
for(int i = 0;i<Files.size();i++)
{
System.out.println(Files.get(i));
}
}
}
I think this code should work well. Although I have tested it just on Windows. But other OS will need at most small changes.
import java.io.*;
public class filedir
{
public static void main(String[] args)
{
try{
Files f = new File("C:\\");//the path required
String a[];
a=f.list();
for (int i = 0; i <a.length; i++) {
System.out.println(a[i]);
}
} catch(Exception e) {
System.err.println(e);
}
}
}
精彩评论