开发者

Find different characters in two strings

开发者 https://www.devze.com 2023-01-09 06:48 出处:网络
How can i find different characters in开发者_JS百科 the strings at same positions? Ex: String string1 = \"Anand has 2 bags and 4 apples\";

How can i find different characters in开发者_JS百科 the strings at same positions? Ex:

String string1 = "Anand has 2 bags and 4 apples";
String n = /* ??? */;
String n2 = /* ??? */;
String string2 = "Anand has " + n + " bags and " + n2 + " apples";

I want n = "2" and n1 = "4".

Please let me know how we can do this? (Space added between words only for clarity purpose . But i can not use Space as delimiter)


You could use a for-loop to loop over the length of the smaller of the strings and check at each position individually


If you are sure about your text in the string remains same you can do something like this -

String string1 ="Anand has 2 bags and 4 apples";
String[] parts = string1.split("\\s+");
System.out.println("n = " + parts[2] + " n1 = " + parts [5]);


You can use the StringTemplate class that i developed (I'd developed a URITemplate class to match restlike uris but have modified it to use strings as well)

  // Licensed Apache2 (http://www.apache.org/licenses/LICENSE-2.0.txt) 
  import java.util.List;

  import java.net.URL;
  import java.net.URLConnection;

  import java.util.Map;
  import java.util.ArrayList;
  import java.util.LinkedHashMap;
  import java.util.regex.Matcher;
  import java.util.regex.Pattern;

  /**
   * <pre>
   *    StringTemplate t = new StringTemplate("/catalog/{categoryId}/products/{productId}/summary");
   *    t.matches("/catalog/23/products/12375/summary"); // returns true
   *    t.match("/catalog/23/products/12375/summary");   // returns a map {categoryId=23, productId=12375}
   * </pre>
   * 
   * @author anaik
   */
  public class StringTemplate {
     /** The meta pattern for  template to match sequence such as: {someVar} */
     private static final Pattern patternPattern = Pattern.compile("\\{([^\\{\\}]+)\\}");
     /** The  pattern string */
     private String stringPattern;
     /** The generated pattern when the stringPattern is parsed */
     private Pattern thisStringPattern;
     /** Variable names found in this pattern in that order */
     private List<String> vars = new ArrayList<String>();

     /**
      * Creates a new StringTemplate from the specified pattern
      * @param Pattern
      */
     private StringTemplate(String stringPattern)  {
        this.stringPattern = stringPattern;
        initialize();
     }

     /**
      * Gets the names of variables - those defined in {variable-name} constructs - in this StringTemplate
      * in the order they were specified
      * @return a list of variables or an empty list if no variables were found
      */
     public List<String> getVars() {
        return vars;
     }

     /**
      * Determine whether the specified <tt>actualString</code> matches with this StringTemplate
      * @param actualString The actual  to match
      * @return true iff successfull match
      */
     public boolean matches(String actualString)  {
        return thisStringPattern.matcher(actualString).matches();
     }

     /**
      * Matches the <tt>actualString</tt> with this StringTemplate and extracts values for all the variables
      * in this template and returns them as an ordered map (keys defined in the same order as that of
      * the StringTemplate. If the match was unsuccessfull, an empty map is returned. Note that this method
      * should be ideally be called after {@link #matches(java.lang.String) } to check whether the 
      * specified actually matches the template
      */
     public Map<String, String> match(String actualString) {
        Matcher m = thisStringPattern.matcher(actualString);
        Map<String, String> map = new LinkedHashMap<String, String>();
        if(m.matches())   {
           int gc = m.groupCount();
           for(int i = 0; i < gc; i++)   {
              int g = i + 1;
              map.put(vars.get(i), actualString.substring(m.start(g), m.end(g)));
           }
        }
        return map;
     }

     private void initialize()  {
        Matcher m = patternPattern.matcher(stringPattern);
        StringBuffer builder = new StringBuffer();

        while(m.find())   {
           String var = m.group(1);
           vars.add(var);
           m.appendReplacement(builder, "(.*)");
        }
        m.appendTail(builder);
        String genPattern = builder.toString();
        thisStringPattern = Pattern.compile(genPattern);
     }

     public static void main(String[] args) throws Throwable  {
        StringTemplate t = new StringTemplate(args[0]);
        System.out.println("Matches with actual Class Identifier: java.lang.String: " + t.matches(args[1]));
        System.out.println("Var values: " + t.match(args[1]));
     }
  }

Compile this and test as follows:

tmp$ java StringTemplate "Anand has {n} bags and {n1} apples" "Anand has 23 bags and 500 apples"

This is the output

 Matches with actual URI: true
 Var values: {n=23, n1=500}

The matches(String) returns the map containing the template variable names and values. This class can be used for matching any string with any number of vars. Its liscensed apache2

If your input string contains regex characters, you will have to escape them:

  input = input.replaceAll("\\$", "\\\\\\$");
  input = input.replaceAll("\\(", "\\\\(");
  input = input.replaceAll("\\)", "\\\\)");
  StringTemplate st = new StringTemplate(input);

Note that you need more accurate regexps for conditions where input string already has characters like "\$"


A regular expression should do this nicely.


If the lengths are not the same:

for(int i = 0; i < Math.min(str1.length, str2.length); i++){
    if(str1.charAt(i) != str2.charAt(i)){
        //Different
    }
}

for(int i = Math.min(str1.length, str2.length);
             i < Math.max(str1.length, str2.length); i++){
    //Each is in one but not the other.
}

If the lengths are the same:

for(int i = 0; i < str1.length; i++){
    if(str1.charAt(i) != str2.charAt(i)){
        //Different
    }
}


I would split the Strings by "spaces", then I would do a for loop looking for numbers in the resulting array. Here's a little example, it's clumpsy but it gets the work done:

import java.util.ArrayList;

public class XXX{
    public static void main(String[] args){
        String str = "Anand has 2 bags and 4 apples";   

        System.out.println("Start...");
        System.out.println(str);
        String words[] = str.split("\\s+");

        ArrayList<String> values = new ArrayList<String>();

        for(String s:words){
            System.out.println(s);
            try{
                Integer.parseInt(s);
                values.add(s);
            }
            catch(NumberFormatException ex){
                System.out.println(s + " is not a number");
            }       
        }

        System.out.println("Anand has " + values.get(0) + " bags and " + values.get(1) + " apples");

    }
}
0

精彩评论

暂无评论...
验证码 换一张
取 消