sort a dictionary according to their values in python [duplicate]

This question already has answers here: Closed 12 years ago.

Possible Duplicate:

Sort by key of dictionary inside a dictionary in Python

I have a dictionary:

d={'abc.py':{'map':'someMap','distance':11},
   'x.jpg':{'map':'aMap','distance':2},....}

Now what I need is: I need to sort d according to their distances?

I tried sorted(d.i开发者_开发百科tems(),key=itemgetter(1,2), but it's not working.

How can it be done?

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You cannot (really) influence the order in which your dict keys appear. If you want to iterate over the sorted keys, you could for instance use

sorted(d.keys(), key=lambda x: d[x]['distance'])

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A dictonary can't be sorted. So you have to convert your data to a list and sort this list. Maybe you convert your dict to a list of tuples (key, value) and sort then.

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You can do it like this:

sorted(d.items(), key=lambda x:x[1]['distance'])