Perform bridge assignment in scala

I want to do this:

var (a, b) = (0, 0)
a = (b = 100) 

but Scala is complaining that

error: type mismatch;
 found   : Uni开发者_如何学编程t
 required: Int

What I want is to assign a and b to the same value. Why Scala make it Unit where it should be Int?

---

Your statement is an assignment, which returns Unit. See this related question for reasons why. You can do this, if you want:

scala> var (a,b) = (0,0)
a: Int = 0
b: Int = 0

scala> a = {b = 100; b}
a: Int = 100

---

scala> var a,b,c,d,e,f,g = 0
a: Int = 0
b: Int = 0
c: Int = 0
d: Int = 0
e: Int = 0
f: Int = 0
g: Int = 0

scala> var f,i,j,k,m,n,o = new Object{}
f: java.lang.Object = $anon$1@11ce012
i: java.lang.Object = $anon$2@baf4ae
j: java.lang.Object = $anon$3@15e68d
k: java.lang.Object = $anon$4@1d3633c
m: java.lang.Object = $anon$5@118317f
n: java.lang.Object = $anon$6@15998cb
o: java.lang.Object = $anon$7@13e6f83

scala>

---

Why ask why? Assignment expressions have type Unit and that's how it is. No chained assignments. Period.

---

You can define a special assignment operator (it must end with a colon as it must be right associative) for your own types, or write a generic wrapper (including implit conversions) for general types. I wouldn't recommend to actually use this, but here it goes:

  case class M[T](var t:T) {
    def =: (m: M[T]):M[T] = {m.t = t ; this}
  }

  implicit def anyToM[T](v:T) = M(v)
  implicit def mToAny[T](m:M[T]) = m.t

  def main(args: Array[String]) {
    var a = M(0)
    var b = M(0)
    var c = M(0)
    a =: b =: c =: 100
    println(a + b + c) //--> 300
  }

I think it is always a bad idea to summon heavy magick in order to save a few keystrokes. In Germany we would call this "to shoot sparrows with a cannon"...

---

case class assign[T](v: T) {                           
  def to(vals: (T => Unit)*) { vals.foreach{ vv => vv(v) } }
}

var (a,b) = (0,0)

assign(39) to (a = _, b = _)

assert(a == 39)
assert(b == 39)

Or you can rename it to emulate a rather simple version of a with statement.

with(20) do (a = _, b = _, print)