开发者

Is it possible to apply a template on xsl parameter before applying the tempates on the xml

开发者 https://www.devze.com 2023-01-08 13:14 出处:网络
I have a xsl parameter which a string. I want to parse that string, split it and for each substring value I want to apply the templa开发者_StackOverflowte in the xsl.

I have a xsl parameter which a string. I want to parse that string, split it and for each substring value I want to apply the templa开发者_StackOverflowte in the xsl.

Is this possible? If so, Can you please advise an optimistic solution?

Thanks


Edit: Missundertood the question, sorry.

The answer is yes.

Input:

<secuence>Item1 Item2 Item3</secuence>

Stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="secuence/text()" name="secuence">
        <xsl:param name="string" select="."/>
        <xsl:param name="separator" select="' '"/>
        <xsl:if test="$string != ''">
            <xsl:choose>
                <xsl:when test="contains($string,$separator)">
                    <xsl:call-template name="secuence">
                        <xsl:with-param name="string" select="substring-before($string,$separator)"/>
                        <xsl:with-param name="separator" select="$separator"/>
                    </xsl:call-template>
                    <xsl:call-template name="secuence">
                        <xsl:with-param name="string" select="substring-after($string,$separator)"/>
                        <xsl:with-param name="separator" select="$separator"/>
                    </xsl:call-template>
                </xsl:when>
                <xsl:otherwise>
                    <!-- Your desired template -->
                    <Item>
                        <xsl:value-of select="$string"/>
                    </Item>
                </xsl:otherwise>
            </xsl:choose>
        </xsl:if>
    </xsl:template>
</xsl:stylesheet>

Result:

<secuence>
    <Item>Item1</Item>
    <Item>Item2</Item>
    <Item>Item3</Item>
</secuence>


Unsure what you mean but copying this pattern may help: XSLT - Best way to split and render comma separated text as HTML

0

精彩评论

暂无评论...
验证码 换一张
取 消