sh equivalent of __FILE__

Is there a sh equivalent of __FILE__, to give me the pathname of the currently executing file? POS开发者_StackOverflow中文版IX solutions preferred, bash acceptable, thanks.

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Try using $0.

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This will grab both the file and the directory

# !/bin/sh

# store where we are
__PWD__=$(pwd)
# go to the current file (i.e. this file)
cd $(dirname $0)
# gives the file name, __FILE__
echo $0
__FILE__=$0
# gives the directory name, __DIR__
echo $(dirname $0)
__DIR__=$(dirname $0)
# this has been a test of the Linux filesystem; we now return you to your previous program.. :)
cd $__PWD__

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For a bash script solution

Getting the source directory of a Bash script from within

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Just a thought:

#!/usr/bin/env bash

# "$0" will expand to the name of the script, as called from the command line
readlink -f $0