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How does function-style cast syntax work?

开发者 https://www.devze.com 2022-12-09 03:12 出处:网络
I guess I am a bit puzzled by the syntax. What does the following mean? typedef char *PChar; hopeItWorks = PChar(开发者_开发技巧 0x00ff0000 );

I guess I am a bit puzzled by the syntax. What does the following mean?

typedef char *PChar;
hopeItWorks = PChar(开发者_开发技巧 0x00ff0000 );


It is equivalent to (PChar) 0x00ff0000 or (char *) 0x00ff0000. Syntactically think of it as invoking a one-argument constructor.


SomeType(args) means explicit constructor call if SomeType is user-defined type and usual c-cast (SomeType)args if SomeType is fundamental type or a pointer.

PChar is equivalent to char * (pointer). Thus hopeItWorks = (char *)0x00ff0000;


typedef char *PChar;

Its typedef of char* to Pchar. Instead of using char* you can define variables with Pchar.

hopeItWorks = PChar( 0x00ff0000 );

Its equivalent to ==>

 hopeItWorks = (char *)( 0x00ff0000 );
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