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Type error in python!

开发者 https://www.devze.com 2023-01-08 02:17 出处:网络
closedset = set() root = (5,6) for u,v开发者_JAVA技巧 in root: if v is not closedset: closedset.add(root)
closedset = set()    


root = (5,6)

for u,v开发者_JAVA技巧 in root:
    if v is not closedset:
       closedset.add(root)
       print closedset

Error:

for u,v in root:

TypeError: unpack non-sequence

What should i do with type of error?


root = [(5,6)]

...should work. for iterates through a list or set, returning first u, then v. If you want to return both parts of the set, you'll have to add itself to a list.


I'm not sure I understand what you're trying to do. Maybe:

roots = [(5, 6), (2, 3)]

for u, v in roots:
  if f not in closed:
    closed.add(v)
    print closed

Note a few changes:

  • roots is now a list of tuples. for u, v in roots will correctly "unpack" each tuple into u and v
  • by if v is not closed your probably meant if f not in closed, if closed is a dictionary of some kind
  • if close.add is a method (of a set?), then it has to be called with parens () and not brackets ()


root = ((5, 6),)

or

u, v = root

Depending on what your intentions are.


for u,v in [root]:
   print u,v

will do what you want.

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