Changing type of ActiveRecord Class in Rails with Single Table Inheritance

I have two types of classes:

BaseUser < ActiveRecord::Base 

and

User < BaseUser

which acts_as_authentic using Authlogic's authentication system. This inheritance is implemented using Single Table Inheritance

If a new user registers, I register him as a User. However, if I already have a BaseUser with the same email, I'd like to change that BaseUser to a User in the database without simply copying all the data over to the User from the BaseUser a开发者_如何学编程nd creating a new User (i.e. with a new id). Is this possible? Thanks.

---

Steve's answer works but since the instance is of class BaseUser when save is called, validations and callbacks defined in User will not run. You'll probably want to convert the instance using the becomes method:

user = BaseUser.where(email: "user@example.com").first_or_initialize
user = user.becomes(User) # convert to instance from BaseUser to User
user.type = "User"
user.save!

---

You can just set the type field to 'User' and save the record. The in-memory object will still show as a BaseUser but the next time you reload the in-memory object will be a User

>> b=BaseUser.new
>> b.class # = BaseUser

# Set the Type. In-Memory object is still a BaseUser
>> b.type='User'
>> b.class # = BaseUser
>> b.save

# Retrieve the records through both models (Each has the same class)

>> User.find(1).class # = User
>> BaseUser.find(1).class # User

---

Based on the other answers, I expected this to work in Rails 4.1:

  def update
    @company = Company.find(params[:id])
    # This separate step is required to change Single Table Inheritance types
    new_type = params[:company][:type]
    if new_type != @company.type && Company::COMPANY_TYPES.include?(new_type)
      @company.becomes!(new_type.constantize)
      @company.type = new_type
      @company.save!
    end

    @company.update(company_params)
    respond_with(@company)
  end

It did not, as the type change would not persist. Instead, I went with this less elegant approach, which works correctly:

  def update
    @company = Company.find(params[:id])
    # This separate step is required to change Single Table Inheritance types
    new_type = params[:company][:type]
    if new_type != @company.type && Company::COMPANY_TYPES.include?(new_type)
      @company.update_column :type, new_type
    end

    @company.update(company_params)
    respond_with(@company)
  end

And here are the controller tests I used to confirm the solution:

  describe 'Single Table Inheritance (STI)' do

    class String
      def articleize
        %w(a e i o u).include?(self[0].to_s.downcase) ? "an #{self}" : "a #{self}"
      end
    end

    Company::COMPANY_TYPES.each do |sti_type|
      it "a newly assigned Company of type #{sti_type} " \
        "should be #{sti_type.articleize}" do
        post :create, { company: attributes_for(:company, type: sti_type) },
             valid_session
        expect(assigns(:company)).to be_a(sti_type.constantize)
      end
    end

    Company::COMPANY_TYPES.each_index do |i|
      sti_type, next_sti_type = Company::COMPANY_TYPES[i - 1],
                                Company::COMPANY_TYPES[i]
      it "#{sti_type.articleize} changed to type #{next_sti_type} " \
        "should be #{next_sti_type.articleize}" do
        company = Company.create! attributes_for(:company, type: sti_type)
        put :update, { id: company.to_param, company: { type: next_sti_type } },
            valid_session
        reloaded_company = Company.find(company.to_param)
        expect(reloaded_company).to be_a(next_sti_type.constantize)
      end
    end
  end