Merge two text files specific position

I need to merge two files with a Bash script.

File_1.txt

TEXT01 TEXT02 TEXT0开发者_开发问答3 TEXT04
TEXT05 TEXT06 TEXT07 TEXT08
TEXT09 TEXT10 TEXT11 TEXT12

File_2.txt

1993.0
1994.0
1995.0

Result.txt

TEXT01 TEXT02 1993.0 TEXT03 TEXT04
TEXT05 TEXT06 1994.0 TEXT07 TEXT08
TEXT09 TEXT10 1995.0 TEXT11 TEXT12

File_2.txt need to be merged at this specific position. I have tried different solutions with multiple do while loops, but they have not been working so far..

---

awk '{
 getline s3 < "file1"
 printf "%s %s %s ",$1,$2,s3
 for(i=3;i<=NF;i++){
    printf "%s ",$i
 }
 print "" 
}END{close(s3)}' file

output

# more file
TEXT01 TEXT02 TEXT03 TEXT04
TEXT05 TEXT06 TEXT07 TEXT08
TEXT09 TEXT10 TEXT11 TEXT12
$ more file1
1993.0
1994.0
1995.0
$ ./shell.sh
TEXT01 TEXT02 1993.0 TEXT03 TEXT04
TEXT05 TEXT06 1994.0 TEXT07 TEXT08
TEXT09 TEXT10 1995.0 TEXT11 TEXT12

---

Why, use cut and paste, of course! Give this a try:

paste -d" " <(cut -d" " -f 1-2 File_1.txt) File_2.txt <(cut -d" " -f 3-4 File_1.txt)

---

This was inspirated by Dennis Williamson's answer so if you like it give there a +1 too!

paste test1.txt test2.txt  | awk '{print $1,$2,$5,$3,$4}'

---

This is a solution without awk.
The interesting is how to use the file descriptors in bash.

#!/bin/sh
exec 5<test2.txt  # open file descriptor 5
cat test1.txt | while read ln
do
    read ln2 <&5 
        #change this three lines as you wish:
    echo -n "$(echo $ln | cut -d ' ' -f 1-2) "
    echo -n "$ln2 "
    echo $ln | cut -d ' ' -f 3-4 
done
exec 5>&-        # Close fd 5

---

Since the question was tagged with 'sed', here's a variant of Vereb's answer using sed instead of awk:

paste File_1.txt File_2.txt | sed -r 's/( [^ ]* [^ ]*)\t(.*)/ \2\1/'

Or in pure sed ... :D

sed -r '/ /{H;d};G;s/^([^\n]*)\n*([^ ]* [^ ]*)/\2 \1/;P;s/^[^\n]*\n//;x;d' File_1.txt File_2.txt

---

Using perl, give file1 and file2 as arguments to:

#/usr/local/bin/perl

open(TXT2, pop(@ARGV));

while (<>) {
    chop($m = <TXT2>);

    s/^((\w+\s+){2})/$1$m /;

    print;
}