php: check if certain item in an array is empty

In PHP, how would one check to see if a specified item (by name, I think - 开发者_StackOverflow中文版number would probably also work) in an array is empty?

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Types of empty (from PHP Manual). The following are considered empty for any variable:

• "" (an empty string)
• 0 (0 as an integer)
• "0" (0 as a string)
• NULL
• FALSE
• array() (an empty array)
• var $var; (a variable declared, but without a value in a class)

So take the example below:

$arr = array(
          'ele1' => 'test',
          'ele2' => false           
       );

1) $arr['ele3'] is not set. So:
isset($arr['ele3']) === false && empty($arr['ele3']) === true
it is not set and empty. empty() checks for whether the variable is set and empty or not.

2) $arr['ele2'] is set, but empty. So:
isset($arr['ele2']) === true && empty($arr['ele2']) === true

1) $arr['ele1'] is set and not empty:
isset($arr['ele1']) === true && empty($arr['ele1']) === false

if you wish to check whether is it empty, simply use the empty() function.

---

if(empty($array['item']))

or

if(!isset($array['item']))

or

if(!array_key_exists('item', $array))

depending on what precisely you mean by "empty". See the docs for empty(), isset() and array_key_exists() as to what exactly they mean.

---

<?php

$myarray=array(1,5,6,5);

$anotherarray=array();

function checkEmpty($array){  
return (count($array)>0)?1:0;  
  }
echo checkEmpty($myarray);

echo checkEmpty($anotherarray);

?>

(for checking if empty result 1 else 0);

Compactness is what I persue in my code.

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i had such situation where i was getting tab it last index of array so if put things together then this might work for the most of cases

<?php 

if( ctype_space($array['index'])  && empty($array['index'])  && !isset($array['index']) ){
   echo 'array index is empty';
}else{
  echo 'Not empty';
}