MySQL (MyISAM) - update field to greatest of two fields from different tables

I have two tables, t1 and t2 with two columns each - id_user and age.

How do I update t1.age to the greatest of t1.age and t2.age for matching ID's and leave t1.age unchanged if there is no matching ID in t2.

Before update:

t1  
+-------+---+   
|id_user|age|  
+-------+---+   
|      1|  5|  
+-------+---+   
|      2| 10|  
+-------+---+   
|      3| 10|  
+-------+---+   

t2
+-------+---+   
|id_user|age|  
+-------+---+   
|      2| 12|  
+-------+---+   
|      3|  8|  
+-------+---+   
|      4| 20|  
+-------+开发者_如何学Python---+   

After update:

t1  
+-------+---+   
|id_user|age|  
+-------+---+   
|      1|  5|  
+-------+---+   
|      2| 12|  
+-------+---+   
|      3| 10|  
+-------+---+   

---

You may want to try:

UPDATE  t1
JOIN    t2 ON (t2.id_user = t1.id_user)
SET     t1.age = t2.age
WHERE   t2.age > t1.age;

Test Case:

CREATE TABLE t1 (id_user int, age int);
CREATE TABLE t2 (id_user int, age int);

INSERT INTO t1 VALUES (1, 5);
INSERT INTO t1 VALUES (2, 10);
INSERT INTO t1 VALUES (3, 10);

INSERT INTO t2 VALUES (2, 12);
INSERT INTO t2 VALUES (3, 8);
INSERT INTO t2 VALUES (4, 20);

Result:

SELECT * FROM t1;
+---------+------+
| id_user | age  |
+---------+------+
|       1 |    5 |
|       2 |   12 |
|       3 |   10 |
+---------+------+
3 rows in set (0.00 sec)

---

UPDATE t1
SET age = T2.age
FROM t1
INNER JOIN t2
ON t2.id_user = t1.id_user
WHERE t2.age > t1.age