How can one strip the left parts and right parts off strings up to a matching expression as in ksh?
For instance:
${name##*/}
${nam开发者_C百科e%/*}
(see http://www.well.ox.ac.uk/~johnb/comp/unix/ksh.html for ksh examples).
I can't seem to figure out a simple way of doing this using re module or string module but I must be missing something.
Ksh:
$ s='abc/def/ghi'
$ echo ${s%%/*}
abc
$ echo ${s%/*}
abc/def
$ echo ${s#*/}
def/ghi
$ echo ${s##*/}
ghi
Python:
>>> s='abc/def/ghi'
>>> print s[:s.find("/")]
abc
>>> print s[:s.rfind("/")]
abc/def
>>> print s[s.find("/")+1:]
def/ghi
>>> print s[s.rfind("/")+1:]
ghi
Edit:
To handle the case in which the pattern is missing, as pointed out by ΤΖΩΤΖΙΟΥ:
>>> s='abc/def/ghi'
>>> t='no slash here'
>>> print s[:s.find("/") % (len(s) + 1)]
abc
>>> print t[:t.find("/") % (len(t) + 1)]
no slash here
>>> print s[:s.rfind("/") % (len(s) + 1)]
abc/def
>>> print t[:t.rfind("/") % (len(t) + 1)]
no slash here
>>> print s[s.find("/")+1:]
def/ghi
>>> print t[t.find("/")+1:]
no slash here
>>> print s[s.rfind("/")+1:]
ghi
>>> print t[t.rfind("/")+1:]
no slash here
${name##*/}
Is equivalent to:
re.match(".*?([^/]*)$")[1]
${name%/*}
Is equivalent to:
re.match("(.*?)[^/]*$")[1]
There is no special status for "strip to the left", "strip to the right", etc. The one general method is re.sub
-- for example, to "strip everything up to the last slash included" ("to the left" as ksh conceptualizes it):
name = re.sub(r'(.*/)(.*)', r'\2', name)
and to strip "the last slash and everything following" ("to the right" per ksh):
name = re.sub(r'(.*)/.*', r'\1', name)
These match as much as possible because the *
in RE patterns is greedy; use *?
instead for non-greedy matching ("as little as possible") instead.
>>> def strip_upto_max(astring, pattern):
"${astring##*pattern}"
return astring.rpartition(pattern)[2]
>>> def strip_from_max(astring, pattern):
"${astring%%pattern*}"
return astring.partition(pattern)[0]
>>> def strip_upto(astring, pattern):
"${astring#*pattern}"
return astring.partition(pattern)[2]
>>> def strip_from(astring, pattern):
"${astring%pattern*}"
return astring.rpartition(pattern)[0]
>>> strip_from("hello there", " t")
'hello'
>>> strip_upto("hello there", " t")
'here'
>>> text= "left/middle/right"
>>> strip_from(text, "/")
'left/middle'
>>> strip_upto(text, "/")
'middle/right'
>>> strip_upto_max(text, "/")
'right'
>>> strip_from_max(text, "/")
'left'
But if your intention is to use it with paths, check whether the os.path.dirname
(${name%/*}
) and os.path.basename
(${name##*/}
) functions have the functionality you require.
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