I have a multiple select and I made a function to check several parameters, each prints a different value in another form:
if ( (tot_v >= 10) || (perc_a < 100) ) {
$("#DA_IDO").val('1');
}
if ( (tot_v > 3) && (tot_v < 10) && (perc_a == 100) ) {
$("#DA_IDO").val('2');
}
if ( (tot_v <= 3) && (perc_a == 100) ) {
$("#DA_IDO").val('3');
}
Then we come to the incriminating if:
开发者_如何学编程if ( !( array in {'One':'', 'Two':'','Three':'','Four':'','Five':''}) ) {
$("#DA_IDO").val('5');
}
This works, but in my mind if array = (One, Ten) the if shouldn't work as at least one of the items in the array is there, instead with an array like the if is triggered.
What am I doing wrong? Is so hard to search for "javascript in" in google .-)
Thanks
I think you're misunderstanding the "in" statement. "in", in javascript, checks to see if the specified value exists as a property (or index in an array). For example:
var x = { a: 'b', c: 'd' };
if('a' in x){
//true
}
if('b' in x){
//false
}
What you're trying to do is determine if any of the values in the array are contained within the object. For this, you'll have to use a loop, something like this:
var possible = {'One':'', 'Two':'','Three':'','Four':'','Five':''};
//removed "array" as a variable name, since it's a bit confusing
for(var i = 0; i < values.length; i++){
if(values[i] in possible){
//exists
}
}
For details, check out the Mozilla docs: https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/in_Operator
Here is a source to give more info on the in
operator:
https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/in_Operator
The Mozilla Developer Central page should clarify what it's for:
The in operator returns true if the specified property is in the specified object.
The left hand side should be the name of a property, e.g. "One". You can't use an array of property names.
It's normal behaviour, your variable 'array
' is an array (as you set it to ('One','Ten')
) so it not int {'One':'', 'Two':'','Three':'','Four':'','Five':''}
(but 'One' is).
The reason by if
block works because you are checking NOT IN ('!
').
I hope I didn't miss anything here.
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