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Step into subroutine call, but not calls made for parameters

开发者 https://www.devze.com 2023-01-07 07:56 出处:网络
func(a(), b.c) When executing the line above in the pdb debugger, using step will actually step into a, and then into the getter for b.c if its atypical (such as being a property), before actually s
func(a(), b.c)

When executing the line above in the pdb debugger, using step will actually step into a, and then into the getter for b.c if its atypical (such as being a property), before actually stepping into func.

Generally I find myself using step followed by r to return from the frames I'm not interested in, and often inexplicably pass over and miss the opportunity to step directly into开发者_如何转开发 func.

How do I step directly into func, or what sequence of debugger commands will guarantee that I end up in func rather than passing over it?


tb func ("temporary break at func") followed by c ("continue") should work.


I would handle this by setting a break at the line number inside func that you're interested in, and then use continue. For example suppose your code looks like this:

110  def func(a1, a2):
111      "" docstring ""
112      first interesting line

then do this:

python -m pdb caller.py
pdb> b 112
pdb> c
0

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