Why Ajax Jquery form click not working vs div that works?_问答_开发者

Ajax Jquery form not working vs div why its happen and how can i fix my error?

view.html-Code with form

not working

<html>
    <head>
 <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
    </head>
    <body>
        <form id="parse-form" action="#" method="post">
            <button type="submit" id="submit-html">submit ajax request without parameters</button>
        </form>
        <div>array values: <div id="array-values"></div></div>
        <script type="text/javascript">
            $(document).ready(function() {
                $('#submit-html').click(function() {
                    $.ajax({
                        url: 'controller.php',
                        type: 'POST',
                        dataType:'json',
                        success: function(data) {
                            alert("response begin");
                            alert(data);
                            $.each(data, function (i, elem) {
                                $('#array-values').append('<div>'+elem+'</div>');
                            });
                        }
                    });
                });
            });
        </script>
    </body>
</html>

开发者_如何学编程

view.html -form replaced by div

working

<html>
    <head>
 <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
    </head>
    <body>
        <div id="parse-form">
            <button type="submit" id="submit-html">submit ajax request without parameters</button>
        </div>
        <div>array values: <div id="array-values"></div></div>
        <script type="text/javascript">
            $(document).ready(function() {
                $('#submit-html').click(function() {
                    $.ajax({
                        url: 'controller.php',
                        type: 'POST',
                        dataType:'json',
                        success: function(data) {
                            alert("response begin");
                            alert(data);
                            $.each(data, function (i, elem) {
                                $('#array-values').append('<div>'+elem+'</div>');
                            });
                        }
                    });
                });
            });
        </script>
    </body>
</html>

controller.php -simple php file that return json array:

<?php
$arr=array ('a'=>1,'b'=>2,'c'=>3,'d'=>4,'e'=>5);
echo json_encode($arr);
?>

Thanks

The form has a default action with a type="submit" button, which is submitting, so you'll need to stop that from happening by adding return false or event.preventDefault() , like this:

$(document).ready(function() {
    $('#submit-html').click(function(e) {
        $.ajax({
            url: 'controller.php',
            type: 'POST',
            dataType:'json',
            success: function(data) {
                alert("response begin");
                alert(data);
                $.each(data, function (i, elem) {
                    $('#array-values').append('<div>'+elem+'</div>');
                });
            }
        });
        return false;
        //or e.preventDefault();
    });
});

Without this, the form is submitting as it normally would with no JavaScript, leaving the page. So effectively it's doing a refresh, instead of AJAX submitting your form (which doesn't have time to complete...because you left :)

An element of type=submit inside a <form> will perform the form request when clicked on.

You need to abort the default behavior by running event.preventDefault() inside the click callback.

My guess is that the form is submitting and refreshing the page before the ajax has a chance to respond.

Try putting return false; at the end of the click handler.

$('#submit-html').click(function() {
  $.ajax({
    url: 'controller.php',
    type: 'POST',
    dataType: 'json',
    success: function(data) {
      alert("response begin");
      alert(data);
      $.each(data, function(i, elem) {
        $('#array-values').append('<div>' + elem + '</div>');
      });
    }
  });
  return false;
});

Of course you'll have the same issue if the user hits Enter in one of the fields. Unless you're preventing the Enter key from submitting the form, you may want to the handle the event using the submit() handler.

$('#parse-form').submit(function() {
  $.ajax({
    url: 'controller.php',
    type: 'POST',
    dataType: 'json',
    success: function(data) {
      alert("response begin");
      alert(data);
      $.each(data, function(i, elem) {
        $('#array-values').append('<div>' + elem + '</div>');
      });
    }
  });
  return false;
});

Try using submit() http://api.jquery.com/submit/ , this should work with keyboard events as well as clicks. You can use serialize() to get any form data into the ajax objects data variable.