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How to get all unique IDs from the list of dicts?

开发者 https://www.devze.com 2022-12-08 23:35 出处:网络
Say you have a list of dicts like this {\'id\': 1, \'other_value\':5} So maybe; items = [{\'id\': 1,开发者_JS百科 \'other_value\':5}, {\'id\': 1, \'other_value2\':6}, {\'id\': 2, \'other_value\':4},

Say you have a list of dicts like this {'id': 1, 'other_value':5}

So maybe;

items = [{'id': 1,开发者_JS百科 'other_value':5}, {'id': 1, 'other_value2':6}, {'id': 2, 'other_value':4}, {'id': 2, 'other_value2':3}]

Now, you can assume this is a small subset of the data. There are maybe thousands. Also the structure isn't specified by me, its given to me.

If I just want to get the IDs out I could do something like this:

ids = [i[id] for i in items]

However, you'll notice there are duplicate id's in the original data. so the question is; how can you tidily get the unique ID's?

I was hoping for something like:

ids = [i[id] for i in items if not in LIST]

but as far as i know there isn't a way to access the list in the generator.

of course I can do a for loop and easily do it that way. I was just curious to know if there was a more concise way of doing this.


if you want unique id's you can use a set:

set(i['id'] for i in items)


set(i['id'] for i in items)

but you might consider another data structure altogether, for example dict of lists:

items = {1: [5, 6], 2: [2, 4]}
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