When I run query number 1:
SELECT id, name, COUNT(name) AS count
FROM markers
WHERE state like 'OR'
group by named
I get the following results:
id name count
14 Alsea 2
76 Applegate Valley 1
3 Ashland 9
64 Beaver 1
26 Bend 1
10 Carlton 2
This is fine, except, I want each instance of a counted name to appear with its respective ID as seen in the result of query number 2:
SELECT id, name, COUNT(name) AS count
FROM markers
WHERE state like 'OR'
group by name, id
Which produces the following results:
id name count
14 Alsea 1
28 Alsea 1
76 Applegate Valley 1
3 Ashland 1
13 Ashland 1
16 Ashland 1
20 Ashland 1
22 Ashland 1
43 Ashland 1
48 Ashland 1
51 Ashland 1
72 Ashland 1
64 Beaver 1
26 Bend 1
10 Carlton 1
27 Carlton 1
Is there a query I can run that will return the id and name from query number 2 and the corresponding count from query number 1 in each row as shown below?
id name count
14 Alsea 2
28 Alsea 2
76 Applegate Valley 1
3 Ashland 9
13 Ashland 9
16 Ash开发者_运维技巧land 9
20 Ashland 9
22 Ashland 9
43 Ashland 9
48 Ashland 9
51 Ashland 9
72 Ashland 9
64 Beaver 1
26 Bend 1
10 Carlton 2
27 Carlton 2
Try this:
SELECT id, name,
(SELECT COUNT(name)
FROM markers im
WHERE state like 'OR'
GROUP BY name
HAVING im.name=m.name) as count
FROM markers m
WHERE state like 'OR'
GROUP BY name, id
You can use:
SELECT t.id,
t.name,
COALESCE(x.cnt, 0) AS count
FROM MARKERS t
LEFT JOIN (SELECT m.name,
COUNT(m.*) AS cnt
FROM MARKERS m
WHERE m.state LIKE 'OR'
GROUP BY n.name) x ON x.name = t.name
WHERE t.state LIKE 'OR'
GROUP BY t.id, t.name
精彩评论