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PHP counter loop not working

开发者 https://www.devze.com 2023-01-06 12:44 出处:网络
I have the following code which should be inserting into the database x amount of times depending on the value given $row[\'max\'] however only 1 is being inserted. Can someone please show me the erro

I have the following code which should be inserting into the database x amount of times depending on the value given $row['max'] however only 1 is being inserted. Can someone please show me the error of my ways! Thanks.

$query = "SELECT * FROM challenges WHERE rate='fixed开发者_开发技巧'";
$query_result = mysql_query($query);

while ($row = mysql_fetch_array($query_result)) {
    $spawn_time = preg_split('/,/', $row['time']);
    $spawn_time_results = count($spawn_time);
    $limitno = $row['max'];
    $spawn_counter = 0;

    while ($spawn_counter <= $spawn_time_results) {
        if ($spawn_time[$spawn_counter] == date("i")) {
            $time = time();
            $insert_instance = "INSERT INTO instances (id,defeated,time)
                                VALUES ('{$row['id']}',0,{$time})";
            $insert_result = mysql_query($insert_instance);
        }
        $spawn_counter++;
    }
}


You never actually use $limitno, so it has no effect...

PS: please use explode instead of preg_split and for instead of this while loop.


Maybe it should be

$insert_instance="INSERT INTO instances (id,defeated,time)
VALUES ({$row['id']},0,{$time})";
0

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