I'm calling a Win32 API function and getting back a string padded with null characters. Trim$()
doesn't remove them. Is there an easier solution then removing them one character 开发者_JAVA技巧at a time?
if it's just padded to the right, you can use something like this:
function ntrim(byval theString as string) as string
dim iPos as long
iPos = instr(theString, chr$(0))
if iPos > 0 then theString = left$(theString, iPos - 1)
ntrim = theString
end function
Loosely based on the last one, maybe this might be better if there's a risk you might have NULLs in your text for some other reason?
Function nTrim2(theString As String) As String
Dim iPos As Long
iPos = Len(theString)
For i = iPos To 0 Step -1
iPos = i
If Mid$(theString, i, 1) <> Chr$(0) Then Exit For
Next
nTrim2 = Left$(theString, iPos)
End Function
In my case Replace() and InStr() don't work with Chr(0) (can't see it not displaying any error), but Nulls can be removed comparing and using Mid(), Left() and Len() as above or in this example:
If Mid$(str, 1, 1) = Chr$(0) Then str = Mid$(str, 2)
If Mid$(str, Len(str), 1) = Chr$(0) Then str = Left$(str, Len(str) - 1)
This is Null removal from ends, for example from objFile.ExtendedProperty("Dimensions")
value, like "?600 x 400?". Nulls (?) are insterted here in Windows 10 but not in Windows XP.
精彩评论