sql left join with distinct correct?

I'm trying to do a join between tables 1 and 2 which have a 1 to many relationship.

table1 has the following fields

• createdat开发者_如何转开发e
• contact
• tkey (surrogate key)

table2 has the following fields

• tkey (primary key)
• status
• userfld1
• description

I want to show all items in table2 with their corresponding items in table1 grouped by table2.userfld1

select distinct t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
from table2 as t2 left join table1 as t1 
      on t2.tkey = t1.tkey 
group by t2.userfld1 

is this correct?

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No that's not correct, you can't select columns that aren't in the group by unless they are contained in an aggregate function. And I think what you are asking for doesn't even make sense. My best guess is that you mean ORDER BY, not GROUP BY:

SELECT DISTINCT t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
FROM table2 t2
LEFT JOIN table1 t1
ON t2.tkey = t1.tkey 
ORDER BY t2.userfld1 

Three other errors that I've fixed:

• SELECT ... FROM not SELECT ... WHERE
• You should join with a table, not a column.
• You had no aliases after the table names, but later refer to these missing aliases.

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I think what you're looking for is order by, not group by, and I also fixed your query:

select t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
where table2 t2 left join table1 t1
      on t2.tkey = t1.tkey 
order by t2.userfld1

Is this what you were looking for?