Is there a better way to write this SQL query?
SELECT *, (SELECT TOP 1 columnB FROM mytable WHERE mytable.columnC = T1.columnC ORDER BY columnD) as firstRecordOfColumnB
FROM
(SELECT * FROM mytable WHERE columnA = 'apple') as T1
Notice that column开发者_如何学运维C is not the primary key.
If the keyColumns is really a key column (i.e. unique), than the query can definitly be written more elegantly and efficiently...
SELECT
*, columnB
FROM
mytable
WHERE
columnA = 'apple'
This might be better in case of performance:
SELECT
*,
(TOP 1 myLookupTable.columnB FROM mytable AS myLookupTable WHERE myLookupTable.keyColumn = mytable.keyColumn) as firstRecordOfColumnB
FROM
mytable
WHERE
columnA = 'apple'
But for the TOP 1 part I don't know any better solution.
Edit: If the keyColumn is unique, the data in firstRecordOfColumnB would be the same as in mytable.columnB. If it's not unique at least you need to sort that data to get a relevant TOP 1, example:
SELECT
*,
(TOP 1 myLookupTable.columnB FROM mytable AS myLookupTable WHERE myLookupTable.keyColumn = mytable.keyColumn
ORDER BY myLookupTable.sortColumn) as firstRecordOfColumnB
FROM
mytable
WHERE
columnA = 'apple'
精彩评论