I am using the regular expression below to weed out any non-Latin characters. As a result, I found that if I use a string larger than 342 characters, the function fails, everything aborts, and the website connection is reset.
I narroed it down to the \p{P} unicode character property, which matches any punctuation chara开发者_JS百科cter.
Does anyone know/see where the problem lies, exactly?
preg_match('/^([\p{P}\p{S}&\p{Latin}0-9]|\s)*$/u', 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa');
If you're "weeding out" non-Latin characters, why not just do this:
preg_replace('/[^\p{Latin}]+/u', '', $s)
EDIT: Okay, so you're trying to validate the input. I was going to say, use this:
preg_match('/^[\p{Latin}]+$/u', $s)
...but it turns out that only matches Latin letters. I was thinking of Java's undocumented shorthand, \p{L1}
, which matches everything in the Latin1 (ISO-8859-1) character set, but in PHP you have to spell it out:
preg_match('/^[\x00-\xFF]+$/u', $s)
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