The idea: I'm setting the value of an input with type="hidden" via regular Javascript or jQuery.
The issue: neither jQuery nor document.getElementById will find the hidden input, even though I'm absolutely sure the selector is correct and there are no conflicting elements.
The code: I can't really post much of it, because it's full of rather complicated PHP that confuses me when I just look at it.
Here's the javascript:
$("#" + input.id.substr(0,2) + "_budget_hidden").val(budg_total);
Note: there's nothing wrong with the selector, and the "input" is a different element that I'm using to reference the hidden.
Here's the HTML:
<input type="hidden" name="s<?=$step_counter?>_budget_hidden"
开发者_JS百科id="s<?=$step_counter?>_budget_hidden" value="0" />
The code is kind of out of context, but it's more of a general problem with Javascript than a syntactical error. Thoughts?
In $("#" + input.id.substr(0,2) + "_budget_hidden").val(budg_total);
you take two chars before the first underscore in your hidden id. However your hidden id have only one char 's'
EDIT
Ok the <?= ?>
was hidden before the question edit.
Do you call your script after the body onload event? EX:
$(document).ready(function(){
$("#" + input.id.substr(0,2) + "_budget_hidden").bind("keyPressed",function(){
$("#" + input.id.substr(0,2) + "_budget_hidden").val(budg_total);
}
});
FYI: We can get the hidden input value using jQuery, even we can also edit any hidden input value using jQuery.
I think your way of getting the hidden value using 'substr' method is causing some problem. You are using like substr(0, 2)
so are sure that the variable $step_variable
is a single digit number, otherwise your code will not return correct result.
I am giving some sample code below, check it once.
Here's the javascript:
var input_id = $("hidden_val").attr("id").substr(1); $("#" + input_id + "_budget_hidden").val(budg_total);
Here's the HTML:
input type="hidden" class="hidden_val" name="s_budget_hidden" id="s" value="0"
I think this will help you. Let me know if you are not following this flow to solve your issue.
I think that input.id.substr(0,2) says to start at the start of the string, take 2 characters and use that.
http://www.w3schools.com/jsref/jsref_substr.asp
Try using Firebug to see what the result of that method call is.
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