The xml file is having the following structure
<Root>
<Child value="A"/>
<Child value="B"/>
<Child value="C"/>
<Child value="D"/>
<Child value="E"/>
</Root>
and the dictonary
Dictionary<int, string> dict = new Dictionary<int, string>();
i need to read the attribute value of "value" from the file and add the sam开发者_如何学Goe to the dictonary as value and index as key
like
dict[1]="A"
dict[2]="B"
dict[3]="C"
dict[4]="D"
dict[5]="E"
for this i'm using the XML to LINQ query as
dict = XDOC.Load(Application.StartupPath + "\\Test.xml").
Descendants("Child").ToDictionary("????", x => x.Attribute("Value").Value);
wat i have to use in the place of "????" in the query
please give a solution to do this
dict = XDOC
.Load(Application.StartupPath + "\\Test.xml")
.Descendants("Child")
.Select((x,i) => new {data=x, index=i})
.ToDictionary(x => x.index, x => x.data.Attribute("Value").Value);
You're immediate problem is that you can't have two entries in the dictionary with the same keys, I'm assuming you'll want some sort of identifier....
int i = 0;
var dic = XDOC.Load(...)
.Root
.Descendants("Child")
.ToDictionary(el => (i++), el => el.Attribute("value").Value);
But then, if its just a sequential collection, why not just use a list:
var list = XDOC.Load(...)
.Root
.Descendants("Child")
.Select(el => el.Attribute("value").Value)
.ToList();
Edit: I didn't know about the element index part, good call peoples!
I assume you don't actually want them all to have the same key, but rather an index value indicating their position in the original set:
var dict = xDoc.Descendants("Child")
.Select((xe, i) => new { Index = i, Element = xe })
.ToDictionary(a => a.Index, a => a.Element.Attribute("value").Value);
If you need access to the index of an element in a sequence, you can use the overload of Enumerable.Select that takes a Func<TSource, int, TResult>
.
dict = XDOC.Load(Application.StartupPath + "\\Test.xml")
.Descendants("Child")
.Select((element, index) =>
new { index, value = element.Attribute("Value").Value })
.ToDictionary(x => x.index, x => x.value);
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