i have an NSNumber that is taken from a string like this
NSNumberFormatter *f = [[NSNumberFormatter alloc]init];
[f setNumberStyle:NS开发者_运维问答NumberFormatterDecimalStyle];
BRNumber = [f numberFromString:BRString];
of course this returns a value but now i wish to do something like
id y = BRNumber + 50;
It seems that this is not possible. So how should i go about doing this.?
You need to get the raw integer before doing the computation, and wrap it back to an NSNumber afterwards.
NSNumber* y = [NSNumber numberWithInt:[BRNumber intValue] + 50];
If you're doing this a lot, you could create a category:
@implementation NSNumber (Arithmetics)
-(NSNumber*)numberByAddingInt:(int)val {
return [NSNumber numberWithInt:[self intValue] + val];
}
@end
then you could use
NSNumber* y = [BRNumber numberByAddingInt:50];
There's no shorter ways, since ObjC doesn't have operator overloading.
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