I am new in xslt. I have the following problem. I need within an xml, to remove a specific attribute (theAttribute
in the example) from a specific element (e.g. div
).
i.e.
<html>
<head>...</head>
<body>
<div id="qaz" theAtribute="44">
</div>
<div id ="ddd" theAtribute="4">
<div id= "ggg" theAtribute="9">
</div>
开发者_运维技巧 </div>
<font theAttribute="foo" />
</body>
</html>
to become
<html>
<head>...</head>
<body>
<div id="qaz">
</div>
<div id ="ddd">
<div id= "ggg">
</div>
</div>
<font theAttribute="foo" />
</body>
</html>
Where attribute theAtribute has been removed. I found this, http://www.biglist.com/lists/xsl-list/archives/200404/msg00668.html based on which i made attempts to find the proper solution.
i.e. <xsl:template match="@theAtribute" />
Which removed it from the whole document... and others like match, if choose, etc. Nothing worked.. :-( can you please help me on this? it sound trivial to me, but with xslt, i cannot cope at all...
Thank you all in advance
What is not working? Do you want the same content, just without the @theAtribute
?
If so, make sure your stylesheet has the empty template for @theAtribute
, but also has an identity template that copies everything else into the output:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!--empty template suppresses this attribute-->
<xsl:template match="@theAtribute" />
<!--identity template copies everything forward by default-->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you only want to suppress certain @theAtribute
, then you can make the match criteria more specific. For instance, if you only wanted to remove that attribute from the div
who's @id="qaz"
, then you could use this template:
<xsl:template match="@theAtribute[../@id='qaz']" />
or this template:
<xsl:template match="*[@id='qaz']/@theAtribute" />
If you want to remove @theAttribute
from all div
elements, then change the match expression to:
<xsl:template match="div/@theAtribute" />
inside the select, you can exclude (or include,) the attribute, using the name function.
For example, <xsl:copy-of select="@*[name(.)!='theAtribute']|node()" />
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:param name="status"/>
<!--If attribute is present change it -->
<xsl:template match="@status" >
<xsl:attribute name="status" select="$status"/>
</xsl:template>
<!-- If attribute is not present add it al last position -->
<xsl:template match="row[ not( @status ) ]" >
<xsl:copy>
<xsl:apply-templates select="@*"/>
<!-- put attribute in the last position -->
<xsl:attribute name="status" select="$status"/>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>
<!--identity template copies everything forward by default-->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I have a xml like:
<row attribute1="value" >some stuff</row>
and I'm adding at end of list of attributes a status from an outside value.
\saxonee\bin\Transform.exe -xsl:my_script.xsl -s:rows.xml status="completed"
<row current_run="2019-07-29 19:00" status="completed">
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