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Why do i need to wrap this code in a cast to short?

开发者 https://www.devze.com 2022-12-08 18:25 出处:网络
If i have some code like the following: short 开发者_高级运维myShortA = 54; short myShortB = 12;

If i have some code like the following:

short 开发者_高级运维myShortA = 54;
short myShortB = 12;
short myShortC = (short)(myShortA - myShortB);

Both operands are shorts and it's going into a short so why do i have to cast it?


Because there's no "short - short" operator. Both operands are promoted to int.

From section 7.7.5 of the C# 3 spec:

The predefined subtraction operators are listed below. The operators all subtract y from x.

  • Integer subtraction:

    int operator –(int x, int y);
    uint operator –(uint x, uint y);
    long operator –(long x, long y); 
    ulong operator –(ulong x, ulong y);
    

    In a checked context, if the difference is outside the range of the result type, a System.OverflowException is thrown.

(And then there's floating point subtraction.)


To make things a little bit easier, you could simply write an extension method like this:

public static class NumericExtensions
{
    public static short Subtract(this short target, short value)
    {
        return (short)(target - value);
    }
}

Others have answered your question... :)

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