select restaurant table entries within a certain distance from current location using php

i have a database table with a list of restaurants including their names, latitudes, and longitudes. i would like to select all the restaurants that are within a certain distance from my current locatio开发者_开发百科n. the current location is determined in the php file (right now i'm just using a static lat & lng). i found code for calculating the distance:

function findDist($lat, $lng){
    $currLat = 33.777563;
    $currLng = -84.389959;

    $currLat = deg2rad ($currLat);
    $sincurrLat = sin ($currLat);
    $lat = deg2rad ($lat);
    $currLng = deg2rad ($currLng);
    $lng = deg2rad ($lng);

    return round((7926 - 26 * $sincurrLat) * asin (min (1, 0.707106781186548 * sqrt ((1 - (sin ($lat) * $sincurrLat) - cos ($currLat) * cos ($lat) * cos ($lng - $currLng))))),4);
}  

but how do i incorporate that into my select query? i tried this:

$query = "SELECT *
FROM
    eateries E
WHERE
    EXISTS
    (
        SELECT *
        FROM
            eateries_hours EH, eateries_type ET
        WHERE
            EH.eateries_id = E.id AND ET.eateries_id = E.id
            AND findDist(E.lat, E.lng) <= .5
    )";

but of course that doesn't work because it's not recognizing the function. can i do a separate query just for lats and lngs at first, calculate the distances, and then join that with the above query somehow? any ideas?

thanks.

---

Take a look at a question that I previously answered. You can create a stored function in MySQL (or other databases) that does this provided that you have the latitudes and longitudes.

DELIMITER $$

DROP FUNCTION IF EXISTS `FindDist` $$
CREATE FUNCTION `FindDist` (lt1 DOUBLE,lg1 DOUBLE,lt2 DOUBLE,lg2 DOUBLE) RETURNS DOUBLE
DETERMINISTIC
BEGIN
    DECLARE dist,eradius DOUBLE;

    SET eradius=3963.1;
    SET dist=Acos(Cos(lt1) * Cos(lg1) * Cos(lt2) * Cos(lg2) + Cos(lt1) * Sin(lg1) * Cos(lt2) * Sin(lg2) + Sin(lt1) * Sin(lt2)) * eradius;
    RETURN dist;
END $$

DELIMITER ;