How to print the function name as a string in Python from inside that function

def appleju开发者_C百科ice(q):
   print THE FUNCTION NAME!

It should result in "applejuice" as a string.

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This also works:

import sys

def applejuice(q):
    func_name = sys._getframe().f_code.co_name
    print func_name

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def applejuice(**args):
    print "Running the function 'applejuice'"
    pass

or use:

myfunc.__name__

>>> print applejuice.__name__
'applejuice'

Also, see how-to-get-the-function-name-as-string-in-python

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import traceback

def applejuice(q):
   stack = traceback.extract_stack()
   (filename, line, procname, text) = stack[-1]
   print procname

I assume this is used for debugging, so you might want to look into the other procedures offered by the traceback module. They'll let you print the entire call stack, exception traces, etc.

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Another way

import inspect 
def applejuice(q):
    print inspect.getframeinfo(inspect.currentframe())[2]

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You need to explain what your problem is. Because the answer to your question is:

print "applejuice"

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This site gave me a decent explanation of how sys._getframe.f_code.co_name works that returns the function name.

http://code.activestate.com/recipes/66062-determining-current-function-name/

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def foo():
    # a func can just make a call to itself and fetch the name
    funcName = foo.__name__
    # print it
    print 'Internal: {0}'.format(funcName)
    # return it
    return funcName

# you can fetch the name externally
fooName = foo.__name__
print 'The name of {0} as fetched: {0}'.format(fooName)

# print what name foo returned in this example
whatIsTheName = foo()
print 'The name foo returned is: {0}'.format(whatIsTheName)