Simple Bash Programming

I am a newbie to BASH so please dont mind my stupid questions because I am not able to get any good sources to learn that.

I want to create a script to display filename and its size. This is what the code is like

开发者_运维百科

filename=$1
if [ -f $filename ]; then
    filesize=`du -b $1`
    echo "The name of file is $1"
    echo "Its size is $filesize"
else
    echo "The file specified doesnot exists"
fi

The output is like this

$ ./filesize.sh aa
The name of file is aa
Its size is 88  aa

But in the last line I don't want to show the name of the file. How do I do that ? I want to do the same thing using wc as well.

---

Use stat(1)

filename=$1
if [ -f $filename ]; then
    filesize=`stat -c %s $1`
    echo "The name of file is $1"
    echo "Its size is $filesize"
else
    echo "The file specified doesnot exists"
fi

See also man 1 stat

---

filesize=`du -b $1 | cut -f 1`

cut -f 1 splits its input by tabs and then outputs the first field (i.e. it returns each line of du's output up to the fist tab character.).

---

All levels of question are accepted here.

You can use awk to only get the first field:

du -b /path/to/file | awk '{print $1}'

Your script would then be something like:

filename=$1
if [ -f ${filename} ]; then
    filesize=$(du -b ${filename} | awk '{print $1}')
    echo "The name of file is ${filename}"
    echo "Its size is ${filesize}"
else
    echo "The file specified does not exists"
fi

You'll notice I've changed a couple of other things as well:

• I prefer $(X) to `X` for capturing output of command simply because they're easier to nest.
• If you've already put $1 into $filename, you may as well use $filename from that point on (the $1 in the awk is a different beast).
• I prefer to put all my variables inside ${} so that it's obvious to both the reader and the shell that ${var}X is $var appended with X, rather than $varX being the non-existent ${varX}.

These are really personal preferences but, as with all my personal preferences, I consider them best practices for the entire IT industry :-)

---

You could use awk to split the output of du at the first space, as follows:

filesize=`du -b $1 | awk '{ print $1; }'`

---

Instead of using du -b $1 use du -b $1 | cut -f 1. It will only include the first field of output of du command, therefore only reporting the size of the file.

---

You can use awk to pick out the first column of data.

filesize=`du -b $1 | awk '{print $1}'`